2cos^2(2x)-2sin^2(2x)=2

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Solution for 2cos^2(2x)-2sin^2(2x)=2 equation: 


Simplifying
2cos2(2x) + -2sin2(2x) = 2

Remove parenthesis around (2x)
2cos2 * 2x + -2sin2(2x) = 2

Reorder the terms for easier multiplication:
2 * 2cos2 * x + -2sin2(2x) = 2

Multiply 2 * 2
4cos2 * x + -2sin2(2x) = 2

Multiply cos2 * x
4cos2x + -2sin2(2x) = 2

Remove parenthesis around (2x)
4cos2x + -2in2s * 2x = 2

Reorder the terms for easier multiplication:
4cos2x + -2 * 2in2s * x = 2

Multiply -2 * 2
4cos2x + -4in2s * x = 2

Multiply in2s * x
4cos2x + -4in2sx = 2

Solving
4cos2x + -4in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4in2sx' to each side of the equation.
4cos2x + -4in2sx + 4in2sx = 2 + 4in2sx

Combine like terms: -4in2sx + 4in2sx = 0
4cos2x + 0 = 2 + 4in2sx
4cos2x = 2 + 4in2sx

Divide each side by '4os2x'.
c = 0.5o-1s-2x-1 + in2o-1s-1

Simplifying
c = 0.5o-1s-2x-1 + in2o-1s-1

Reorder the terms:
c = in2o-1s-1 + 0.5o-1s-2x-1

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